X Arcos complementares OA B A B cos sen M N /2 x x + /2 sen( /2 x) = cos x cos( /2 x) = sen x.

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    17-Apr-2015

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  • Slide 1
  • x Arcos complementares OA B A B cos sen M N /2 x x + /2 sen( /2 x) = cos x cos( /2 x) = sen x
  • Slide 2
  • OA B A B cos sen M x N /2 + x + /2 sen( /2 + x) = cos x cos( /2 + x) = sen x
  • Slide 3
  • O A B A B cos sen M x N 3 /2 + x +3 /2 sen(3 /2 + x) = cos x cos(3 /2 + x) = sen x
  • Slide 4
  • Exemplo 3/23/2 3 / 2 3/23/2 cos 3/23/2 sen 3301503060 3/23/2 cos 3 / 2 3/23/2 3/23/2 sen 3001206030 (270+x)(90+x)(90x) (3 /2+x)( /2+x)( /2x) x sen( /2 x) = cos x cos( /2 x) = sen x sen( /2 + x) = cos x cos( /2 + x) = senx sen(3 /2 + x) = cos x cos(3 /2 + x) = sen x
  • Slide 5
  • OA B A B cos sen M x N /2 + x + /2 sen( /2 + x) = cos x cos( /2 + x) = sen x tg x tg( /2 + x) = cotg x
  • Slide 6
  • Resumo: Funes seno, co-seno e tangente Funoy = sen xy = cos xy = tg x Domnio x k + /2 Perodo 2 2 Mnimo1 Mximo11+ Imagem[1, 1] ], + [
  • Slide 7
  • Domnio, perodo e conjunto imagem de funes seno FunoDomnioPerodoImagem y = sen (x) y = sex (2x) 2 y = sen (x/2)1 y = 2sen (x /2) 11+ y = 2sen (2x + /2) [1, 1] ], + [ y = 1 + 3sen (2x) y = 1 + 2sen (x + /2) y = sen 2 (x) y = 1 + sen 2 (8x)

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